What Is The Binary Format For The Following Decimal Ip Address?
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What is the binary format for the following decimal IP address? 131.9.202.111
Answer: The binary form of the IP address 131.9.202.111 is 10000011.00001001.11001010.01101111
The combination of the IP address and subnet mask gives the numeric value to the interface. The combination of the address is used, in the absence of the subnet mask, the IP address is the dark address, and the subnet number is without an IP address. The length of the address is 32 bits, and they are divided into 4 parts which are called octets and have 8 bits in them. The octet is separated by the (.) periods. Let’s take a look at the process to convert the decimal IP address to binary.
For the IP address conversion, take 1.1.1.1 one octet is chosen at a time as
1 decimal=1 binary.
1 decimal=1 binary.
1 decimal=1 binary.
1 decimal=1 binary.
As we know the IP address is 32 bit which means 8 bits are present in one octet, that’s why make the other bits of the octets 0 such as 1.1.1.1 are equal to binary numbers:
00000001 00000001 00000001 00000001
With the help of the table listed below, it is simple to convert the 255.255.255.0
As we know 255=11111111
The binary form of the given subnet mask starts with the bottom row which is 27 =128. let’s find how many 128 in 255 :
255-128=127 and the process begins like this:
127-64=63
63 – 32 = 31
31 – 16 = 15
15 – 8 = 7
7 – 4 = 3
3 – 2 = 1
1 – 1 = 0
All the bits are used for the binary form of decimal 255 .as the last octet is 0 the binary form is 00000000. The subnet mask in binary form is:
11111111 11111111 11111111 00000000
So, the IP address and subnet mask in binary form are :
subnet mask :00000001 00000001 00000001 00000001
IP address: 11111111 11111111 11111111 00000000